描述
实现一个算法，可以将小写数字转换成大写数字。
输入
输入一个整数。范围在0～450亿之间。
输出
输出对应的大写数字，以“元整”结尾。 大写数字要符合汉语读写习惯。
输入样例
0 5 233 1001 40607 8900000000
输出样例
零元整 伍元整 贰佰叁拾叁元整 壹仟零壹元整 肆万零陆佰零柒元整 捌拾玖亿元整
AC代码：
#include <bits/stdc++.h>
#include<vector>
#include<stack>
#include<sstream>
using namespace std;
char* num[] = {"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
string func1(string s)
{
bool isZero = false;
int k = 0;
/*while(s[k]-'0'==0)
{
s[k]='*';
k++;
}*/
k = s.size()-1;
while(s[k]-'0'==0)
{
s[k]='*';
k--;
}
for(int i = 0; i<s.size(); i++)
{
if(s[i]-'0' != 0)
{
isZero = false;
}
else if(s[i]-'0' == 0 && isZero == true)
{
s[i] = '*';
}
else if(s[i]-'0' == 0 && isZero == false)
{
isZero = true;
}
}
return s;
}
string func(string s)
{
string result = "";
int k = 0;
for(int i = s.size()-1; i>=0; i--)
{
if(s[i] =='*')
{
k++;
continue;
}
if(s[i]-'0' >= 0 && s[i]-'0' <= 9)
{
if(k == 1 &&s[i]-'0' != 0)
{
result ="拾" +result;
}
else if(k == 2 &&s[i]-'0' != 0)
{
result ="佰" +result;
}
else if(k == 3 &&s[i]-'0' != 0)
{
result ="仟" +result;
}
result = num[s[i]-'0'] + result ;
k++;
}
}
return result;
}
int main()
{
// char *unit[] = {"十","百","千"，"万","亿"};仟佰拾
string s;
bool isZero = false;
while(cin>>s)
{
string s1 ="";
string s2 = "";
string s3 = "";
string result = "";
if(s == "0")
{
cout<<"零元整"<<endl;
continue;
}
if(s.length()> 0 && s.length()<=4)
{
s1 = func1(s);
s1 = func(s1);
cout<<s1;
}
else if(s.length()> 4 && s.length()<=8)
{
s1 = s.substr(s.length()-4,4);
s1 = func1(s1);
s1 = func(s1);
s2 = s.substr(0,s.length()-4);
s2 = func1(s2);
s2 = func(s2);
cout<<s2<<"万";
cout<<s1;
}
else if(s.length()> 8 && s.length()<=12)
{
int num = s.length();
s1 = s.substr(s.length()-4,4);
s1 = func1(s1);
s1 = func(s1);
s2 = s.substr(s.length()-8,4);
s2 = func1(s2);
s2 = func(s2);
s3 = s.substr(0,s.length()-8);
s3 = func1(s3);
s3 = func(s3);
cout<<s3<<"亿";
if(s2!="")
{
cout<<s2<<"万";
}
cout<<s1;
}
cout<<"元整"<<endl;
}
}